union a {int a_int1;double a_double;int a_int2;};typedef struct{a a1;char y;} b;class c
union a {
int a_int1;
double a_double;
int a_int2;
};
typedef struct
{
a a1;
char y;
} b;
class c
{
double c_double;
b b1;
a a2;
};
输出cout<<sizeof(c)<<endl;的结果?
union a {
int a_int1;
double a_double;
int a_int2;
};
typedef struct
{
a a1;
char y;
} b;
class c
{
double c_double;
b b1;
a a2;
};
输出cout<<sizeof(c)<<endl;的结果?
设有以下说明和定义:
typedef union {long i; int k[5]; char c;} DATE;
struct data { int cat; DATE cow; double dog;} too;
DATE max;
则语句 printf("%d",sizeof(struct date)+sizeof(max));的执行结果是:___52__
设有以下说明和定义:
typedef union {long i; int k[5]; char c;} DATE;
struct data { int cat; DATE cow; double dog;} too;
DATE max;
则语句 printf("%d",sizeof(struct date)+sizeof(max));的执行结果是:___52____
下面关于“联合”的题目的输出?
a)
#i nclude <stdio.h>
union
{
int i;
char x[2];
}a;
void main()
{
a.x[0] = 10;
a.x[1] = 1;
printf("%d",a.i);
}
设有以下说明和定义:
typedef union {long i; int k[5]; char c;} DATE;
struct data { int cat; DATE cow; double dog;} too;
DATE max;
则语句 printf("%d",sizeof(struct date)+sizeof(max));的执行结果是:___52____
b)
main()
{
union{ /*定义一个联合*/
int i;
struct{ /*在联合中定义一个结构*/
char first;
char second;
}half;
}number;
number.i=0x4241; /*联合成员赋值*/
printf("%c%c\n", number.half.first,
mumber.half.second);
number.half.first='a'; /*联合中结构成员赋值
*/
number.half.second='b';
printf("%x\n", number.i);
getch();
}
n(8,9),Union(1,8),Union(3,10),Union(3,11),Union(3,12),Union(3,13),Union(14,15),Union(16,17),Union(14,16),Union(1,3),Union(1,14),要求:
(1)以任意方式执行Union;
(2)根据树的高度执行Union;
(3)根据树中结点个数执行Union。