已知unsigned int x = 012, y = 0x0f; 则表达式x & (y^y) 的结果为()。
A.15
B.1
C.10
D.0
A.15
B.1
C.10
D.0
程序改错
class mml
{
private:
static unsigned int x;
public:
mml(){ x++; }
mml(static unsigned int &) {x++;}
~mml{x--;}
pulic:
virtual mon() {} = 0;
static unsigned int mmc(){return x;}
......
};
class nnl:public mml
{
private:
static unsigned int y;
public:
nnl(){ x++; }
nnl(static unsigned int &) {x++;}
~nnl{x--;}
public:
virtual mon() {};
static unsigned int nnc(){return y;}
......
};
代码片断:
mml* pp = new nnl;
..........
delete pp;
评价下面的代码片断:
unsigned int zero = 0;
unsigned int compzero = 0xFFFF;
/*1's complement of zero */
评价下面的代码片断:
unsigned int zero = 0;
unsigned int compzero = 0xFFFF;
/*1's complement of zero */
以下代码能够编译通过吗,为什么?
unsigned int const size1 = 2;
char str1[ size1 ];
unsigned int temp = 0;
cin >> temp;
unsigned int const size2 = temp;
char str2[ size2 ];
unsigned short array[]={1,2,3,4,5,6,7};
int i = 3;
*(array + i) = ?
switch(c) 语句中c可以是int, long, char, float, unsigned int 类型。
12 . 下面的代码输出是什么,为什么?
void foo(void)
{
unsigned int a = 6;
int b = -20;
(a+b > 6) puts("> 6") : puts("<= 6");
}
12 . 下面的代码输出是什么,为什么?
void foo(void)
{ unsigned int a = 6;
int b = -20;
(a+b > 6) puts("> 6") : puts("<= 6");
}
以下程序的输出结果是()
#include<stdio.h>
main()
{ unsigned short a=65537; int b;
printf("%d/n" ,b=a);
}
1,要对绝对地址0x100000赋值,我们可以用
(unsigned int*)0x100000 = 1234;
那么要是想让程序跳转到绝对地址是0x100000去执行,应该怎么做?